A) \[mgH\]
B) \[\sqrt{2gH}\]
C) \[T\frac{p-1}{p}\]
D) Zero
Correct Answer: B
Solution :
At B, the velocity is maximum using conservation of mechanical energy \[\Delta PE=\Delta KE\] Þ \[mgH=\frac{1}{2}m{{v}^{2}}\] Þ \[v=\sqrt{2gH}\]
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