A) Zero
B) \[m\theta \sqrt{\frac{g}{l}}\]
C) \[\frac{m\theta }{l}\sqrt{\frac{l}{g}}\]
D) \[\frac{m}{l}2\pi \sqrt{\frac{l}{g}}\]
Correct Answer: A
Solution :
No momentum will be transferred because, at extreme position the velocity of bob is zero.You need to login to perform this action.
You will be redirected in
3 sec