A) \[T=2\pi \sqrt{\frac{l}{g}}\]
B) \[T=2\pi \sqrt{\frac{l}{2g}}\]
C) Zero
D) Infinite
Correct Answer: D
Solution :
This is the case of freely falling lift and in free fall of lift effective g for pendulum will be zero. So \[\Rightarrow y=2\sin 1000\ t+\sin 999\ t+\sin 1001\ t\]
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