A) \[{{\tan }^{-1}}\frac{a}{g}\] in the forward direction
B) \[{{\tan }^{-1}}\frac{a}{g}\] in the backward direction
C) \[{{\tan }^{-1}}\frac{g}{a}\] in the backward direction
D) \[{{\tan }^{-1}}\frac{g}{a}\] in the forward direction
Correct Answer: B
Solution :
In accelerated frame of reference, a fictitious force (pseudo force) ma acts on the bob of pendulum as shown in figure. Hence, \[\tan \theta =\frac{ma}{mg}=\frac{a}{g}\]\[\Rightarrow \] \[\theta ={{\tan }^{-1}}\left( \frac{a}{g} \right)\] in the backward direction.You need to login to perform this action.
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