JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Simple Pendulum

  • question_answer
    There is a simple pendulum hanging from the ceiling of a lift. When the lift is stand still, the time period of the pendulum is T. If the resultant acceleration becomes \[g/4,\] then the new time period of the pendulum is               [DCE 2004]

    A)            0.8 T                                         

    B)            0.25 T

    C)            2 T 

    D)            4 T

    Correct Answer: C

    Solution :

               \[T\propto \frac{1}{\sqrt{g}}\]Þ \[\frac{{{T}_{2}}}{{{T}_{1}}}=\sqrt{\frac{{{g}_{1}}}{{{g}_{2}}}}\]\[=\sqrt{\left( \frac{g}{g/4} \right)}\]Þ \[{{T}_{2}}=2{{T}_{1}}=2T\]


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