A) \[\frac{T}{\sqrt{3}}\]
B) \[\frac{T}{3}\]
C) \[\frac{\sqrt{3}}{2}T\]
D) \[\sqrt{3}\,T\]
Correct Answer: C
Solution :
For stationary lift \[{{T}_{1}}=2\pi \sqrt{\frac{l}{g}}\] For ascending lift with acceleration a, \[{{T}_{2}}=2\pi \sqrt{\frac{l}{g+a}}\] \[\Rightarrow \] \[\frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{g+a}{g}}\Rightarrow \frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{g+\frac{g}{3}}{g}}=\sqrt{\frac{4}{3}}\Rightarrow {{T}_{2}}=\frac{\sqrt{3}}{2}T\]
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