A) T
B) \[\frac{T}{4}\]
C) \[\frac{2T}{\sqrt{5}}\]
D) \[2T\sqrt{5}\]
Correct Answer: C
Solution :
In stationary lift \[T=2\pi \sqrt{\frac{l}{g}}\] In upward moving lift \[{T}'=2\pi \sqrt{\frac{l}{(g+a)}}\] (\[a=\]Acceleration of lift) \[\Rightarrow \] \[\frac{{{T}'}}{T}=\sqrt{\frac{g}{g+a}}=\sqrt{\frac{g}{\left( g+\frac{g}{4} \right)}}=\sqrt{\frac{4}{5}}\] \[\Rightarrow {T}'=\frac{2T}{\sqrt{5}}\]
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