JEE Main & Advanced Mathematics Straight Line Question Bank Slope of line, Equation of line in different forms

  • question_answer
    The equation to the straight line passing through the point \[(a{{\cos }^{3}}\theta ,\ a{{\sin }^{3}}\theta )\] and perpendicular to the line \[x\sec \theta +y\,\text{cosec}\,\theta =a,\] is                                                                 [AMU 1975]

    A)            \[x\cos \theta -y\sin \theta =a\cos \ 2\theta \]

    B)            \[x\cos \theta +y\sin \theta =a\cos \ 2\theta \]

    C)            \[x\sin \theta +y\cos \theta =a\cos \ 2\theta \]                           

    D)            None of these

    Correct Answer: A

    Solution :

               \[x\cos \theta -y\sin \theta =a\text{ }({{\cos }^{4}}\theta -{{\sin }^{4}}\theta )=a\cos 2\theta \].


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