A) \[bx-ay=0\]
B) \[bx+ay-2ab=0\]
C) \[bx+ay=0\]
D) None of these
Correct Answer: A
Solution :
Equation of line perpendicular to \[ax+by+c=0\] is \[bx-ay+\lambda =0\] .....(i) It passes through (a, b) So, from equation (i), \[ab-ab+\lambda =0\Rightarrow \lambda =0\] So equation of line is \[bx-ay=0\].You need to login to perform this action.
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