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JEE Main & Advanced Mathematics Straight Line Question Bank Slope of line, Equation of line in different forms

  • question_answer
    The equation of the line passing through the point \[({x}',\ {y}')\] and perpendicular to the line \[y{y}'=2a\,(x+{x}')\] is

    A)            \[x{y}'+2ay+2a{y}'-{x}'{y}'=0\]

    B)            \[x{y}'+2ay-2a{y}'-{x}'{y}'=0\]

    C)            \[x{y}'+2ay+2a{y}'+{x}'{y}'=0\]                                          

    D)            \[x{y}'+2ay-2a{y}'+{x}'{y}'=0\]

    Correct Answer: B

    Solution :

               Slope =\[\frac{-{y}'}{2a}\].                    Hence equation is\[{y}'x+2ay={y}'{x}'+2a{y}'\].


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