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JEE Main & Advanced Mathematics Straight Line Question Bank Slope of line, Equation of line in different forms

  • question_answer
    The equation of the line parallel to the line \[2x-3y=1\] and passing through the middle point of the line segment joining the points (1, 3) and (1, - 7), is

    A)            \[2x-3y+8=0\]                        

    B)            \[2x-3y=8\]

    C)            \[2x-3y+4=0\]                        

    D)            \[2x-3y=4\]

    Correct Answer: B

    Solution :

               Midpoint \[\equiv \left( \frac{1+1}{2},\frac{3-7}{2} \right)=(1,-2)\]                    Therefore required line is \[2x-3y=k\Rightarrow 2x-3y=8\].


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