A) \[2x-3y+8=0\]
B) \[2x-3y=8\]
C) \[2x-3y+4=0\]
D) \[2x-3y=4\]
Correct Answer: B
Solution :
Midpoint \[\equiv \left( \frac{1+1}{2},\frac{3-7}{2} \right)=(1,-2)\] Therefore required line is \[2x-3y=k\Rightarrow 2x-3y=8\].You need to login to perform this action.
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