A) \[x-y+1=0,\ \ x+y+1=0\]
B) \[x-y-1=0,\ \ x+y-1=0\]
C) \[x-y-1=0,\ \ x+y+1=0\]
D) None of these
Correct Answer: C
Solution :
Here \[c=-1\]and \[m=\tan \theta =\tan {{45}^{o}}=1\] (Since the line is equally inclined to the axes, so \[\theta ={{45}^{o}}\]) Hence equation of straight line is \[y=\pm (1.\,x)-1\] Þ \[x-y-1=0\]and \[x+y+1=0\].You need to login to perform this action.
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