A) \[2{a}'y-2bx=ab-{a}'{b}'\]
B) \[2ay-2{b}'\ x=ab-{a}'{b}'\]
C) \[2ay-2{b}'x={a}'b-a{b}'\]
D) None of these
Correct Answer: B
Solution :
Mid point of \[AB=E\text{ }\left( \frac{a+{a}'}{2},\frac{b+{b}'}{2} \right)\]and mid point of \[CD=F\text{ }\left( \frac{{a}'-a}{2},\frac{b-{b}'}{2} \right)\]. Hence equation of line EF is \[y-\frac{b+{b}'}{2}\]\[=\frac{b-{b}'-b-{b}'}{{a}'-a-a-a'}\left( x-\frac{a+{a}'}{2} \right)\] On simplification, we get \[2ay-2{b}'x-=ab-{a}'{b}'\].You need to login to perform this action.
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