A) \[x+2y=0\]
B) \[2x+y=0\]
C) \[x-2y=0\]
D) \[2x-y=0\]
Correct Answer: C
Solution :
Here D (1, 1) therefore equation of line AD is given by\[2x+y-3=0\]. Thus the line perpendicular to AD is \[x-2y+k=0\]and it passes through B, so\[k=0\]. Hence required equation is\[x-2y=0\].You need to login to perform this action.
You will be redirected in
3 sec