A) \[3x+4y+3=0\]
B) \[3x+4y=0\]
C) \[4x-3y+3=0\]
D) \[4x-3y=3\]
Correct Answer: A
Solution :
Point of intersection \[y=-\frac{21}{5}\]and \[x=\frac{23}{5}\] \[\therefore \] \[3x+4y=\frac{3(23)+4(-21)}{5}=\frac{69-84}{5}=-3\]. Hence, required line is\[3x+4y+3=0\].You need to login to perform this action.
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