A) \[x\sqrt{3}+y+8=0\]
B) \[x\sqrt{3}-y=8\]
C) \[x\sqrt{3}-y=8\]
D) \[x-\sqrt{3}\ y+8=0\]
Correct Answer: A
Solution :
Slope \[=-\sqrt{3}\] \[\therefore \] Line is \[y=-\sqrt{3}x+c\]Þ \[\sqrt{3}x+y=c\] Now \[\frac{c}{2}=|4|\Rightarrow c=\pm \text{ }8\Rightarrow x\sqrt{3}+y=\pm \,8\].You need to login to perform this action.
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