A) \[5x+3y+8=0\]
B) \[3x-5y+8=0\]
C) \[5x+3y+11=0\]
D) \[3x-5y+11=0\]
Correct Answer: A
Solution :
The point of intersection of \[5x-6y-1=0\]and \[3x+2y+5=0\]is\[(-1,\,-1)\]. Now the line perpendicular to \[3x-5y+11=0\]is \[5x+3y+k=0\], but it passes through \[(-1,-1)\] Þ \[-5-3+k=0\Rightarrow k=8\] Hence required line is\[5x+3y+8=0\].You need to login to perform this action.
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