JEE Main & Advanced Mathematics Straight Line Question Bank Slope of line, Equation of line in different forms

  • question_answer
    The equation of the straight line joining the point \[(a,\ b)\]to the point of intersection of the lines \[\frac{x}{a}+\frac{y}{b}=1\] and \[\frac{x}{b}+\frac{y}{a}=1\] is

    A)            \[{{a}^{2}}y-{{b}^{2}}x=ab\ (a-b)\]                                 

    B)            \[{{a}^{2}}y+{{b}^{2}}y=ab\ (a+b)\]

    C)            \[{{a}^{2}}y+{{b}^{2}}x=ab\]                                         

    D)            \[{{a}^{2}}x+{{b}^{2}}y=ab\ (a-b)\]

    Correct Answer: A

    Solution :

               The given lines intersect at \[\left( \frac{ab}{a+b},\frac{ab}{a+b} \right)\] and join of this with (a, b) will have slope \[\frac{{{b}^{2}}}{{{a}^{2}}}\]. Now proceed.


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