A) \[y+x-\sqrt{3}=0\]
B) \[y-x+2=0\]
C) \[y-\sqrt{3}\,x-2=0\]
D) \[\sqrt{3}y-x+2\sqrt{3}=0\]
Correct Answer: D
Solution :
\[y=mx+c\]; \[\because \] \[m=\tan 30{}^\circ \]\[=\frac{1}{\sqrt{3}}\]; \[c=-2\] \[\therefore \]\[y=\frac{x}{\sqrt{3}}-2\] Þ \[\sqrt{3}y-x+2\sqrt{3}=0\].You need to login to perform this action.
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