A) \[x=2\]
B) \[x+y=3\]
C) \[x=3\]
D) \[x=4\]
Correct Answer: C
Solution :
Required line should be, \[(3x-y+2)+\lambda (5x-2y+7)=0\] ?..(i) Þ \[(3+5\lambda )x-(2\lambda +1)y+(2+7\lambda )=0\] Þ \[y=\frac{3+5\lambda }{2\lambda +1}x+\frac{2+7\lambda }{2\lambda +1}\] ?..(ii) As the equation (ii), has infinite slope, \[2\lambda +1=0\] Þ \[\lambda =-1/2\] putting \[\lambda =-1/2\] in equation (i) we have \[(3x-y+2)+(-1/2)(5x-2y+7)=0\]Þ \[x=3\].You need to login to perform this action.
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