A) \[5x+3y+1=0\]
B) \[3x+5y+1=0\]
C) \[5x-3y-1=0\]
D) \[3x-5y+1=0\]
Correct Answer: A
Solution :
Equation of a line perpendicular to \[3x-5y+7=0\] is \[5x+3y+\lambda =0\] ??(i) \[\because \] This equation passes through \[(1,\,-2)\] \ \[5\times 1+3\times (-2)+\lambda =0\] Þ \[5-6+\lambda =0\]Þ \[\lambda =1\] \ Equation is\[5x+3y+1=0\].You need to login to perform this action.
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