A) \[x+2y-a=0\]
B) \[x+2y=2a\]
C) \[3x+4y-4a=0\]
D) \[3x-4y+4a=0\]
Correct Answer: D
Solution :
Obviously, other line AB will pass through (0, a) and \[(2a,k)\]. But as we are given \[AB=AC\] \[\Rightarrow k=\sqrt{4{{a}^{2}}+{{(k-a)}^{2}}}\]Þ \[k=\frac{5a}{2}\] Hence the required equation is \[3x-4y+4a=0\].You need to login to perform this action.
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