A) \[y=x,\ y+x=1\]
B) \[y=x,\ x+y=2\]
C) \[2y=x,\ y+x=\frac{1}{3}\]
D) \[y=2x,\ y+2x=1\]
Correct Answer: A
Solution :
Co-ordinates of the vertices of the square are \[A(0,\,0),\] \[B(0,\,1),\] \[C(1,\,1)\] and \[D(0,\,1)\]. Now the equation of AC is \[y=x\] and of \[BD\] is \[y-1=-\frac{1}{1}(x-0)\] \[\Rightarrow x+y=1\].You need to login to perform this action.
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