A) \[2x+2y+\sqrt{2}=0\]
B) \[2x+2y-\sqrt{2}=0\]
C) \[2x-2y+\sqrt{2}=0\]
D) None of these
Correct Answer: A
Solution :
Gradient of \[BC=-1\] and its equation is \[x+y+4=0\]. Therefore the equation of line parallel to \[BC\]is \[x+y+\lambda =0\]. Also it is \[\frac{1}{2}\]unit distant from origin. Thus \[\frac{\lambda }{\sqrt{2}}=\frac{1}{2}\Rightarrow \lambda =\frac{\sqrt{2}}{2}.\] Hence the required equation of line is \[2x+2y+\sqrt{2}=0\].You need to login to perform this action.
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