A) 900
B) 494
C) 602
D) 802
Correct Answer: A
Solution :
Density \[\rho =\frac{nA}{N{{(a)}^{3}}}\] where n = 2 for bcc structure , A = 39 ´ 10?3 kg, N = 6.02 ´ 1023, a \[=\frac{2}{\sqrt{3}}d=\frac{2}{\sqrt{3}}\times (4.525\times {{10}^{-10}})m\] (d = nearest neighbour distance = distance between centres of two neighbouring atoms \[=\frac{a}{\sqrt{2}}\]) On putting the values we get r = 907
You need to login to perform this action.
You will be redirected in
3 sec
