A) { - 1, 2}
B) {1, 2}
C) { - 1, - 2}
D) {1, - 2}
Correct Answer: D
Solution :
\[|x-2|\,={{x}^{2}}\]\[\Rightarrow x-2={{x}^{2}}\] or \[2-x={{x}^{2}}\] \[\Rightarrow {{x}^{2}}-x+2=0\] or \[{{x}^{2}}+x-2=0\] \[\Rightarrow {{x}^{2}}+x-2=0\]\[[\because {{x}^{2}}-x+2=0\]does not gives any real root] \[\Rightarrow (x+2)(x-1)=0\,\,\,\Rightarrow x=-2,\,1\].You need to login to perform this action.
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