A) Rational
B) Non-real
C) Irrational
D) Zero
Correct Answer: A
Solution :
\[D\equiv {{b}^{2}}-4ac={{(-a-c)}^{2}}-4ac\] \[(\because a+b+c=0)\] \[={{(a+c)}^{2}}-4ac={{(a-c)}^{2}}\ge 0\] Hence roots are rational.You need to login to perform this action.
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