A) \[\frac{p-q}{r-p},1\]
B) \[\frac{q-r}{p-q},1\]
C) \[\frac{r-p}{p-q},1\]
D) \[1,\frac{q-r}{p-q}\]
Correct Answer: C
Solution :
Given equation is \[(p-q){{x}^{2}}+(q-r)x+(r-p)=0\] \[x=\frac{(r-q)\pm \sqrt{{{(q-r)}^{2}}-4(r-p)(p-q)}}{2(p-q)}\] Þ \[x=\frac{(r-q)\pm (q+r-2p)}{2(p-q)}\Rightarrow x=\frac{r-p}{p-q},1\]You need to login to perform this action.
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