A) 1, 4
B) \[1,-4\]
C) \[1,-8\]
D) 1, 8
Correct Answer: C
Solution :
\[{{x}^{2/3}}+{{x}^{1/3}}-2=0\]Þ \[{{({{x}^{1/3}})}^{2}}+1({{x}^{1/3}})-2=0\] Let \[a={{x}^{1/3}},\] then \[{{a}^{2}}+a-2=0\]Þ \[a=1,-2\] Hence\[x=1,-8\](by \[a={{x}^{1/3}}\]).You need to login to perform this action.
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