A) 0
B) 1
C) 0, 1
D) None
Correct Answer: D
Solution :
Given equation is \[\sqrt{3x+1}+1=\sqrt{x}\] Þ \[\sqrt{3x+1}=\sqrt{x}-1\] Squaring on both sides, we get \[3x+1=x+1-2\sqrt{x}\] \[\Rightarrow 2\sqrt{x}+2x=0\] (irrational function) Thus \[x\ne 0\] and\[x\ne 1\], since equation is non-quadratic equation.You need to login to perform this action.
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