A) x is an irrational number
B) \[2<x<3\]
C) \[x=3\]
D) None of these
Correct Answer: C
Solution :
\[x=\sqrt{6+x}\], \[x>0\,\,\Rightarrow {{x}^{2}}=6+x,x>0\] \[\Rightarrow {{x}^{2}}-x-6=0,\,x>0\] \[\Rightarrow x=3,x>0\].You need to login to perform this action.
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