A) 3
B) 1
C) 2
D) 0
Correct Answer: B
Solution :
\[{{\log }_{4}}(x-1)={{\log }_{2}}(x-3)\] \[\Rightarrow x-1={{(x-3)}^{2}}\] \[\Rightarrow {{x}^{2}}-7x+10=0\] \[\Rightarrow (x-5)(x-2)=0\] \[\therefore x=5,\]2 but \[x-3<0\] when \[x=2\] \[\therefore \] only solution is \[x=5\] \[\therefore \] Hence number of solution is one.You need to login to perform this action.
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