A) \[{{a}^{2}}+{{b}^{2}}({{m}^{2}}+1)=0\]
B) \[{{b}^{2}}+{{a}^{2}}({{m}^{2}}+1)=0\]
C) \[{{a}^{2}}-{{b}^{2}}({{m}^{2}}+1)=0\]
D) \[{{b}^{2}}-{{a}^{2}}({{m}^{2}}+1)=0\]
Correct Answer: C
Solution :
Roots are equal, then \[{{B}^{2}}-4AC=0\] Þ \[4{{a}^{2}}{{m}^{2}}=4({{m}^{2}}+1)({{a}^{2}}-{{b}^{2}})\] Þ \[{{a}^{2}}-{{b}^{2}}({{m}^{2}}+1)=0\].You need to login to perform this action.
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