A) 2
B) 3
C) 4
D) 5
Correct Answer: C
Solution :
Ifa, b, g are the roots of the equation. \[{{x}^{3}}-p{{x}^{2}}+qx-r=0\] \[\therefore {{(\alpha +\beta )}^{-1}}+{{(\beta +\gamma )}^{-1}}+{{(\gamma +\alpha )}^{-1}}=\frac{{{p}^{2}}+q}{pq-r}\] Given, \[p=0,\,\,q=4,\,\,\,r=-1\] Þ \[\frac{{{p}^{2}}+q}{pq-r}=\frac{0+4}{0+1}=4\].You need to login to perform this action.
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