A) 1, 1, 1, 1
B) 2, 2, 2, 2
C) 3, 1, 3, 1
D) 1, 2, 1, 2
Correct Answer: A
Solution :
Let \[f(x)={{x}^{4}}-4{{x}^{3}}+6{{x}^{2}}-4x+1=0\] Þ \[(x-1)({{x}^{3}}-3{{x}^{2}}+3x-1)=0\] Þ \[(x-1){{(x-1)}^{3}}=0\]Þ \[x=1,\,1,\,1,\,1\]You need to login to perform this action.
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