A) \[n\pi +\frac{\pi }{4}\]
B) \[n\pi -\frac{\pi }{4}\]
C) \[n\pi \pm \frac{\pi }{4}\]
D) \[2n\pi \pm \frac{\pi }{4}\]
Correct Answer: C
Solution :
\[2{{\tan }^{2}}\theta ={{\sec }^{2}}\theta \Rightarrow 2{{\tan }^{2}}\theta ={{\tan }^{2}}\theta +1\] \[\Rightarrow \] \[{{\tan }^{2}}\theta =1={{\tan }^{2}}\left( \frac{\pi }{4} \right)\Rightarrow \theta =n\pi \pm \frac{\pi }{4}\].
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