JEE Main & Advanced Mathematics Trigonometric Equations Question Bank Solution of trigonometrical equations

  • question_answer
    If \[\cos \theta +\sec \theta =\frac{5}{2}\], then the general value of \[\theta \]is

    A) \[n\pi \pm \frac{\pi }{3}\]

    B) \[2n\pi \pm \frac{\pi }{6}\]

    C) \[n\pi \pm \frac{\pi }{6}\]

    D) \[2n\pi \pm \frac{\pi }{3}\]

    Correct Answer: D

    Solution :

    \[{{\cos }^{2}}\theta -\frac{5}{2}\cos \theta +1=0\] \[\Rightarrow \] \[\cos \theta =\frac{(5/2)\pm \sqrt{(25/4)-4}}{2}=\frac{5\pm 3}{4}\] Rejecting (+) sign, \[\Rightarrow \] \[\cos \theta =\frac{1}{2}=\cos \left( \frac{\pi }{3} \right)\Rightarrow \theta =2n\pi \pm \frac{\pi }{3}\].


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