A) \[2n\pi +\frac{\pi }{6}\]
B) \[2n\pi \pm \frac{\pi }{6}\]
C) \[n\pi \pm \frac{\pi }{6}\]
D) \[n\pi \pm \frac{\pi }{3}\]
Correct Answer: C
Solution :
\[{{\sec }^{2}}\theta +{{\tan }^{2}}\theta =\frac{5}{3}\], also\[{{\sec }^{2}}\theta -{{\tan }^{2}}\theta =1\] \[\Rightarrow \] \[{{\tan }^{2}}\theta =\frac{1}{3}={{\tan }^{2}}\left( \frac{\pi }{6} \right)\Rightarrow \theta =n\pi \pm \frac{\pi }{6}\].You need to login to perform this action.
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