A) \[\theta =n\pi +\frac{\pi }{2}-\alpha \]
B) \[\theta =n\pi -\frac{\pi }{2}+\alpha \]
C) \[\theta =n\pi +\frac{\pi }{2}+\alpha \]
D) \[\theta =n\pi -\frac{\pi }{2}-\alpha \]
Correct Answer: A
Solution :
\[\tan \theta =\cot \alpha \Rightarrow \tan \theta =\tan \left( \frac{\pi }{2}-\alpha \right)\] \[\Rightarrow \] \[\theta =n\pi +\frac{\pi }{2}-\alpha \].
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