A) 4 s
B) 0.4 s
C) 104 s
D) 1.2 s
Correct Answer: B
Solution :
Distance of the boy from the wall = 70m distance travelled by sound (before echo is heard) \[=2\times 70m,\]speed of sound\[=350m{{s}^{1}}\] \[Time=\frac{distance}{speed}\] \[=\frac{2\times 70}{350}=0.4s\]You need to login to perform this action.
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