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A) \[\text{III}\to \text{IV}\to II\to \text{I}\]
B) \[\text{III}\to \text{IV}\to I\to \text{II}\]
C) \[\text{IV}\to \text{III}\to I\to \text{II}\]
D) \[\text{IV}\to \text{III}\to II\to \text{I}\]
Correct Answer: C
Solution :
In a wave, the number of crests or troughs appearing per second is its frequency. The numbers of crests appearing per unit time in waves I, II, III, and IV are 2, 1, 4, and 8 respectively. Hence, the frequencies of waves I, II, III, and IV are 2 Hz, 1 Hz, 4 Hz, and 8 Hz respectively. Hence, the arrangement of the waves according to their decreasing frequencies is, IV ?! III ?! I ?! II The correct answer is C.
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