A) wavelength of wave I is greater than that of wave II
B) frequency of wave I is greater than that of wave II
C) amplitude of wave I is less than that of wave II
D) period of wave I is less than that of wave II
Correct Answer: A
Solution :
The distance between two consecutive crests or troughs is known as the wavelength of a wave. It is clear from the given figure that the distance between two consecutive crests of wave I is greater than that between two consecutive crests of wave II. Hence, it can be concluded that the wavelength of wave I is greater than that of wave II. The correct answer is A.You need to login to perform this action.
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