Answer:
We know, \[V=\frac{\lambda }{T}\] \[=\frac{0.332m}{{{10}^{-3}}s}\] \[=332m{{s}^{1}}\] For new wave, 'v' remains the same. Hence, \[332=\frac{\lambda }{{{10}^{-4}}}\] \[\Rightarrow \]\[\lambda =332\times {{10}^{-4}}m\] \[=0.0332m\] Also \[n=\frac{1}{T}\] \[=\frac{1}{{{10}^{-4}}}Hz\] \[={{10}^{4}}Hz\]
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