A) \[12\,\,cm\]
B) \[18\,\,cm\]
C) \[24\,\,cm\]
D) \[32\,\,cm\]
Correct Answer: A
Solution :
The distance between the two consecutive compressions or rarefactions (wavelength) is out of phase by\[{{360}^{o}}\]. The distance between two points which is \[{{60}^{o}}\]out of phase \[=\frac{1}{6}\times wavelength=\frac{1}{6}\times \frac{velocity}{frequency}\] \[=\frac{1}{6}\times \frac{360}{500}=0.12\,\,m=12\,\,cm\]
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