| A sound wave travelling in a medium is represented as shown in figure. |
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| If vibrating source of sound makes 360 oscillations in 2 minutes, then the amplitude, wavelength and frequency of the sound wave respectively are (Take velocity of sound as\[342\text{ }m\text{ }{{s}^{-1}}\]) |
A) 1 m, 114 m and 3 Hz
B) 2 m, 3 m and 14 Hz
C) 1 m, 5 m and 20 Hz
D) 1 m, 100 m and 10 Hz.
Correct Answer: A
Solution :
Here, amplitude of sound wave = 1 m (given) Wavelength of sound wave,\[\lambda =\frac{{{v}_{s}}}{v}...\left( i \right)\] In 2 minutes, number of oscillations = 360 In 1 second, number of oscillations \[=\frac{360}{2\times 60}=3\] \[\therefore \] Frequency of sound wave, \[\text{v=3}\,\,\text{Hz}\] Put the value of \[v\]in (i), \[\therefore \] Wavelength of sound wave, \[\lambda =\frac{342}{3}=114m\]
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