A) Symmetric matrix
B) Skew symmetric matrix
C) Null matrix
D) None of these
Correct Answer: B
Solution :
Since \[A,B\] are symmetric \[\Rightarrow \] \[A={A}'\] and \[B={B}'\] \[\therefore \] \[(AB-BA{)}'=(AB{)}'-(BA{)}'={B}'{A}'-{A}'{B}'\] \[=-({A}'{B}'-{B}'{A}')=-(AB-BA)\] \[\Rightarrow \] \[(AB-BA)\] is skew-symmetric.You need to login to perform this action.
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