A) 2 km
B) 5 km
C) 2 m
D) 5 m
Correct Answer: A
Solution :
| [a] Here, a = 3 km/h 6 = 4 km/h \[{{t}_{1}}=5\min =\frac{5}{60}=\frac{1}{12}h\] and \[{{t}_{2}}=5\min \] \[=\frac{5}{60}=\frac{1}{12}h\] \[\therefore \] Distance between starting point of Ruby and Multiplex = D \[=\frac{ab}{(b-a)}({{t}_{1}}+{{t}_{2}})\] \[=\frac{3\times 4}{(4-3)}\times \left( \frac{1}{12}+\frac{1}{12} \right)\] \[=\frac{3\times 4}{1}\times \frac{2}{12}=2\,km\] |
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