SSC Quantitative Aptitude Speed, Time and Distance Question Bank Speed Time and Distance (I)

  • question_answer
    A man driving at \[\frac{3}{4}\text{th}\] of his original speed reaches his destination 20 min later than the usual time. Then, the usual time is

    A) 45 min

    B) 60 min

    C) 48 min

    D) 120 min

    Correct Answer: B

    Solution :

    [b] Let original speed and time be S and T, respectively. Then, \[S\times T=\frac{3}{4}S\times \left( T+\frac{20}{60} \right);\] \[\frac{4}{3}T=\left( T+\frac{1}{3} \right)\] \[\Rightarrow \] \[\frac{4}{3}T-T=\frac{1}{3}\] \[\Rightarrow \] \[\frac{T}{3}=\frac{1}{3}\] \[\Rightarrow \]\[T=1\,h=60\min \]


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