A) 20 km
B) 21 km
C) 22 km
D) 24 km
Correct Answer: D
Solution :
[d] \[\because \]\[x=30,\]\[y=24,\]\[{{t}_{1}}=\frac{6}{60},\] \[{{t}_{2}}=\frac{6}{60}\] \[\therefore \] Required distance \[=\frac{xy\,({{t}_{1}}+{{t}_{2}})}{x-y}\] \[=\frac{30\times 24}{30-24}\times \left( \frac{6}{60}+\frac{6}{60} \right)=24\] |
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